So, basically, we have to increase a variable to keep track of the inversions and return it to the caller. If you know how to implement merge-sort, large part of the job is done.
There main problem is that they set the timeout very tightly, and you should get a few problem respecting them, especially if you are using an implementation language that is not among the fastest ones.
I use Python here, so I had to be careful go get an accepted solution. The have a nice, well readable python 3 code accepted I had to submit is a PyPy. Getting something accepted as Python3 required some more job.
In the end I came out with this stuff:
def count_inversions(a): return merge_sort(a, 0, len(a) - 1)The required count_inversions() simply calls my adapted merge-sort() function.
Beside sorting, it also stores in the variable result the count of all the inversions, and then will return it.
def merge_sort(a, left, right): result = 0 if left < right: center = left + (right - left) // 2 result += merge_sort(a, left, center) result += merge_sort(a, center + 1, right) result += merge(a, left, center, right) return resultAs you see, no surprise, it's a standard merge-sort implementation.
I have spent some sweating on merge, to save to most time I could without getting something still readable:
def merge(data, left, center, right): def merge(data, left, center, right): merged =  # 1 result = 0 # 2 i = left # 3 j = center + 1 while i <= center and j <= right: # 4 if data[i] > data[j]: # 5 result += (center - i + 1) merged.append(data[j]) j += 1 else: merged.append(data[i]) i += 1 for i in range(i, center+1): # 6 merged.append(data[i]) for j in range(j, right+1): merged.append(data[j]) data[left:right+1] = merged # 7 return result1. We need some temporary area where storing the merged data. I use this list.
2. Keep track of the swaps happening here.
3. The main while below runs on two loop variables, i and j, representing the indexes to the left and right elements.
4. Loop until there is at least one element on the left and one on the right to be merged.
5. If an element on the left is bigger than the ones on the right, we have a swap. Or better, as many swaps as the number of elements still on the right.
6. Take care of the leftover.
7. Replace the part of the list on which we worked with the merged elements.
Fast enough to get accepted. Test case and python script on GitHub.